Reading the parent form's submission status from a child without prop drilling.
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reactreact-19hooksforms
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Reusable submit button reading form status
Run Playgroundimport { useFormStatus } from 'react-dom';
function SubmitButton() {
const { pending } = useFormStatus(); // status of the nearest parent <form>
return <button disabled={pending}>{pending ? 'Submitting…' : 'Submit'}</button>;
}
async function submit(formData) {
await new Promise((r) => setTimeout(r, 1000));
alert('Submitted: ' + formData.get('email'));
}
export default function App() {
return (
<div style={{ fontFamily: 'sans-serif', padding: 24 }}>
<form action={submit}>
<input name="email" placeholder="email@example.com" />
<SubmitButton />
</form>
<p style={{ color: '#666' }}>The button disables itself via useFormStatus() — no props passed down.</p>
</div>
);
}05
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