Explain amortized cost.
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Understand the problem
amortized
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Read the code
Dynamic array with doubling
Run Playgroundclass DynamicArray:
def __init__(self):
self.data = [None]
self.size = 0
def push(self, x):
if self.size == len(self.data): # full -> O(n) resize, but rare
new = [None] * (2 * len(self.data))
for i in range(self.size):
new[i] = self.data[i]
self.data = new
self.data[self.size] = x # O(1) amortized
self.size += 1
# --- demo --- 5 pushes trigger resizes at cap 1,2,4 -> still O(1) amortized
arr = DynamicArray()
for x in range(5): arr.push(x)
print(arr.size, arr.data[:arr.size]) # 5 [0, 1, 2, 3, 4]05
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