Question presented to candidate: "If compose(f, g, h)(x) and pipe(h, g, f)(x) are given, do they produce the same result? Walk me through exactly why or why not."
What a strong answer should cover:
- 📌 Interview term: function composition — building a new function by chaining several smaller functions together, where each one's output becomes the next one's input.
- 📌 Interview term:
compose(...fns)— applies the functions right-to-left — the RIGHTMOST function runs first on the initial input, and each result flows leftward through the rest. - 📌 Interview term:
pipe(...fns)— applies the functions left-to-right — the LEFTMOST function runs first, and each result flows rightward — the mirror image ofcompose. - 📌 Interview term: the real, direct answer to the prompt — verified directly:
compose(square, addOne, double)(3)andpipe(double, addOne, square)(3)(the identical three functions, in correspondingly REVERSED order) genuinely produce the identical result (49) — confirmingcomposeandpipeare genuinely mirror images of each other, not fundamentally different operations. - A precise answer names that function ORDER genuinely matters when the functions don't commute — verified directly:
compose(square, addOne, double)(3)(49) andcompose(double, addOne, square)(3)(20, the SAME three functions in a genuinely different order) produce genuinely DIFFERENT results, confirming this is not a trivial or order-independent operation.
Clarifying questions expected:
- None — this is a definitional/comparison question; directly answering the prompt's own reversed-order equivalence question with real proof is the strong signal.
Code / implementation expected: Yes — a real, generic compose/pipe implementation, verified producing identical results with correspondingly reversed function order, plus a real proof that order genuinely changes the result, is the clearest demonstration.