Implement TimeLimitedCache (LeetCode 2622) with expiry

Question

Accepted Answer

**Approach:** Map stores `{value, timer}`. On `set`, clear old timer if exists, set new `setTimeout` to delete.

```javascript
class TimeLimitedCache {
  constructor() { this.map = new Map(); }
  set(key, value, duration) {
    const exists = this.map.has(key);
    if (exists) clearTimeout(this.map.get(key).timer);
    const timer = setTimeout(() => this.map.delete(key), duration);
    this.map.set(key, { value, timer });
    return exists;
  }
  get(key) { return this.map.has(key) ? this.map.get(key).value : -1; }
  count() { return this.map.size; }
}

// Demo
const cache = new TimeLimitedCache();
console.log(cache.set(1, 42, 100)); // false
console.log(cache.get(1)); // 42
console.log(cache.set(1, 100, 100)); // true (unexpired existed)
console.log(cache.count()); // 1
setTimeout(()=> console.log(cache.get(1)), 150); // -1 (expired)
class SimpleTTL {
  constructor(){ this.m=new Map(); }
  set(k,v,dur){ const has=this.m.has(k) && this.m.get(k).exp > Date.now(); this.m.set(k,{v, exp: D

Implement TimeLimitedCache (LeetCode 2622) with expiry

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KEEP THE
STREAK ALIVE.

Understand the problem

Attempt it yourself

Study the solution

Solution ready — 2 min read

Join the discussion

Discussion (0)

KEEP THESTREAK ALIVE.

KEEP THE
STREAK ALIVE.