Explain merging two sorted lists.
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How do you merge two sorted linked lists?
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01
Understand the problem
linked-list
02
Attempt it yourself
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03
Study the solution
Use a dummy head and a tail pointer; repeatedly attach the smaller of the two list heads and advance it. When one list runs out, append the rest of the other. O(m+n) time, O(1) extra space. The dummy node avoids special-casing the head.
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04
Read the code
Dummy-head iterative merge
Run Playgroundclass ListNode:
def __init__(self, val, nxt=None):
self.val, self.next = val, nxt
def merge_two_lists(l1, l2):
dummy = tail = ListNode(0)
while l1 and l2:
if l1.val <= l2.val:
tail.next, l1 = l1, l1.next
else:
tail.next, l2 = l2, l2.next
tail = tail.next
tail.next = l1 or l2
return dummy.next
# --- demo ---
def build(vals):
head = None
for v in reversed(vals): head = ListNode(v, head)
return head
def to_list(head):
out = []
while head: out.append(head.val); head = head.next
return out
print(to_list(merge_two_lists(build([1, 4]), build([2, 5])))) # [1, 2, 4, 5]05
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