Explain merging k sorted lists.
Skip to solutionKEEP THE
hardDSA
How do you merge k sorted lists?
1.1k views
01
Understand the problem
heaplinked-list
02
Attempt it yourself
Sketch your approach before reading the solution — that's what interviews test.
Nudge consolestandby
Stuck? Beam a request up — the console returns a conceptual nudge that guides your logic without spoiling the implementation.
03
Study the solution
Put the head of each list into a min-heap, repeatedly pop the smallest and push its successor — O(N log k) for N total elements. Alternatively merge lists pairwise (divide and conquer) for the same complexity without a heap.
Solution ready — 2 min read
Classified // press E to declassify
04
Read the code
Min-heap of list heads
Run Playgroundimport heapq
class ListNode:
def __init__(self, val, nxt=None):
self.val, self.next = val, nxt
def merge_k_lists(lists):
heap = []
for i, node in enumerate(lists):
if node:
heapq.heappush(heap, (node.val, i, node)) # i breaks ties
dummy = tail = ListNode(0)
while heap:
val, i, node = heapq.heappop(heap)
tail.next = node
tail = node
if node.next:
heapq.heappush(heap, (node.next.val, i, node.next))
return dummy.next
# --- demo ---
def build(vals):
head = None
for v in reversed(vals): head = ListNode(v, head)
return head
def to_list(head):
out = []
while head: out.append(head.val); head = head.next
return out
merged = merge_k_lists([build([1, 4, 5]), build([1, 3, 4]), build([2, 6])])
print(to_list(merged)) # [1, 1, 2, 3, 4, 4, 5, 6]05
Join the discussion
Discussion (0)
Sign in to join the discussion.
No responses yet. Be the first to share what you think.
Transmission complete // awaiting log
KEEP THE
STREAK ALIVE.
Dossier 103 of 127 decoded in the Data Structures & Algorithms track. One more won't hurt.